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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2017
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In the electrochemical cell - <br> $Zn|ZnSO_4 \; (0.01 M) || CuSO_4 \; (1.0 M) | Cu$, the emf of this Daniel cell is $E_1$. When the concentration of $ZnSO_4$ is changed to $0.1 M$ and that of $CuSO_4$ changed to $0.01 M$, the emf changes to $E_2$. From the followings, which one is the relayionship between $E_1$ and $E_2$ ? (Given , $\frac{RT}{F} = 0.059$)


( A ) $E_1 = E_2$
( B ) $E_1 < E_2$
( C ) $E_1 > E_2$
( D ) $E_2 = 0 \neq E_1$

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