A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is :

Question

( A ) $\frac{4 \pi}{\sqrt{5}}$
( B ) $\frac{\sqrt{5}}{2 \pi}$
( C ) $\frac{\sqrt{5}}{\pi}$
( D ) $\frac{2 \pi}{\sqrt{3}}$