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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2017
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A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k''. Then k' : k'' is :


( A ) 1:6
( B ) 1:14
( C ) 1:9
( D ) 1:11
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