Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2018
Answer
Comment
Share
Q)

The power radiated by a black body is P and it radiates maximum energy at wavelength, $\lambda_0$. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength $\frac{3}{4} \lambda_D$, the power radiated by it becomes nP. The value of n is


( A ) $\frac{81}{256}$
( B ) $\frac{256}{81}$
( C ) $\frac{4}{5}$
( D ) $\frac{3}{4}$

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...