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If $\large\frac{1}{a},\frac{1}{b},\frac{1}{c} $ are in A.P., then the equation $a(b-c)x^2+b(c-a)x+c(a-b)=0$ has

$\begin{array}{1 1} \text{(A) Real and distinct roots} \\ \text{(B) Real and equal roots} \\ \text{(C) No real roots } \\ \text{(D) cannot say } \end{array} $

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