If 5 moles of N2 is combined with 12 moles of $H_2$ as per given reaction. $N_2 + 3 H_2 → 2 NH_3$

Question

$\begin{array}{1 1} \text{(a) 12 moles reacting} \\ \text{ (b) 8 moles reacting} \\ \text{ (c) 4 moles reacting} \\ \text{ (d) 2 moles reacting} \end{array}$