$\Large \int \normalsize\frac{dx}{\sqrt{9x-4x^2}}$ equals

Question

$$\begin{array}{1 1}(A)\;\frac{1}{9}\sin^{-1}\bigg(\frac{9x-8}{8}\bigg)+C \\ (B)\;\frac{1}{2}\sin^{-1}\bigg(\frac{8x-9}{9}\bigg)+C\\(C)\;\frac{1}{3}\sin^{-1}\bigg(\frac{9x-8}{8}\bigg)+C \\ (D)\;\frac{1}{2}\sin^{-1}\bigg(\frac{9x-8}{9}\bigg)+C\end{array}$$