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Let $A =\begin{pmatrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \end{pmatrix} \; (10) B = \begin{pmatrix} 4 &2 &2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \end{pmatrix} $. If $B$ is the inverse of matrix $A$, then $\alpha$ is


( A ) -1
( B ) -2
( C ) 2
( D ) 5

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