If $ \begin{align*} x = e^{{y+e}^{^{y+...to\; \alpha}}}, \; x >0 \end{align*}$, then $\frac{dy}{dx}$ is

Question

( A ) $\frac{x}{1+x}$
( B ) $\frac{1-x}{x}$
( C ) $\frac{1}{x}$
( D ) $\frac{1+x}{x}$