Excess of $KI$ reacts with $CuSO_4$ solution and then $Na_2S_2O_3$ solution is added to it. Which of the statements is incorrect for this reaction ?

Question

( A ) $CuI_2$ is formed
( B ) $Na_2S_2O_3$ is oxidized
( C ) $Cu_2I_2$ is reduced
( D ) Evolved $I_2$ is reduced