If the coefficients of $r^{th}$, $(r+1)^{th}$ and $(r+2)^{th}$ terms in the binomial expansion of $(1 + y)^m$ are in AP, then $m$ and $r$ satisfy the equation :

Question

( A ) $m^2 - m(4r - 1) + 4r^2 - 2 = 0$
( B ) $m^2 - m(4r + 1) + 4r^2 - 2 = 0$
( C ) $m^2 - m(4r - 1) + 4r^2 - 2 = 0$
( D ) $m^2 - m(4r + 1) + 4r^2 + 2 = 0$