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JEEMAIN and NEET
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JEEMAIN PAST PAPERS
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2005
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Q)
If $x$ is so small that $x^3$ and higher powers of $x$ may be neglected, then $\frac{(1+x)^{3/2} - (1+\frac{1}{2}x)^3}{(1-x)^{1/2}}$ may be approximated as :
( A ) $-\frac{3}{8} x^2$
( B ) $3{x} - \frac{3}{8}x^2$
( C ) $\frac{x}{2} - \frac{3}{8}x^2$
( D ) $1 - \frac{3}{8}x^2$
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