If the angle $\theta$ between the line $\frac{x+1}{1} = \frac{y-1}{2} = \frac{z-2}{2}$ and the plane $2x - y + \sqrt{\lambda} z+4 = 0$ is such that $\sin \theta = \frac{1}{3}$. The value of $\lambda$ is :

Question

( A ) $\frac{5}{3}$
( B ) $\frac{3}{4}$
( C ) $-\frac{4}{3}$
( D ) $-\frac{3}{5}$