The potential energy of a 1 kg particle free to move along the $x$-axis is given by $V(x) = (\frac{x^4}{4} - \frac{x^2}{2} ) J$ <br> The total mechanical energy of the particle is $2J$. Then, the maximum speed (in m/s) is:

Question

( A ) $3 / \sqrt{2}$
( B ) $ \sqrt{2}$
( C ) $1 / \sqrt{2}$
( D ) $2$