The following mechanism has been proposed for the reaction of $NO$ with $Br_2$ to form $NOBr$ : <br> $NO(g) + Br_2 (g) \rightleftharpoons NOBr_2 (g)$ <br> $NOBr_2 (g) + NO (g) \to 2NOBr (g)$ <br> If the second step is the rate determining step, the order of the reaction with respect to $NO (g)$ is :

Question

( A ) 0
( B ) 2
( C ) 3
( D ) 1