# If the lines $3x - 4y - 7=0$ and $2x- 3y-5=0$ are two diameters of a circle of area $49\; \pi\; square$ units, the equation of the circle is :
( A ) $x^2 + y^2 - 2x + 2y - 47 = 0$
( B ) $x^2 + y^2 + 2x - 2y - 47 = 0$
( C ) $x^2 + y^2 - 2x + 2y - 62 = 0$
( D ) $x^2 + y^2 + 2x - 2y - 62= 0$