If $0 < x < \pi$ and $\cos x + \sin x = \frac{1}{2}$, then $\tan x$ is:

Question

( A ) $\frac{(1- \sqrt{7} )}{4}$
( B ) $-\frac{(4 + \sqrt{7} )}{3}$
( C ) $\frac{(4 - \sqrt{7} )}{3}$
( D ) $\frac{(1+ \sqrt{7} )}{4}$