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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation
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The gravitational field due to mass distribution is $ E= k/x^3$ in the x direction where k is a constant. Taking gravitational potential to be zero at infinity, its value at a distance x is

\[(a)\;\frac{k}{x} \quad (b)\;\frac{k}{2x} \quad (c)\;\frac{k}{x^2}\quad (d)\;\frac{k}{2x^2} \]

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