In an AC circuit the voltage applied is $E= E_0 \sin \omega t$. The resulting current in the circuit is $I = I_0 \sin (\omega t - \frac{\pi}{2})$. The power consumption in the circuit is given by :

Question

( A ) $P = \sqrt{2} E_0 I_0$
( B ) $P = zero$
( C ) $P = \frac{E_0 I_0}{2}$
( D ) $P = \frac{E_0 I_0}{\sqrt{2}}$