In a Young's double slit experiment the intensity at a point where the path difference is $\frac{\lambda}{6}$ ($\lambda$ being the wavelength of the light used) is $I$. If $I_0$ denotes the maximum intensity, $I/ I_0$ is equal to :

Question

( A ) $\frac{\sqrt{3}}{2}$
( B ) $\frac{1}{2}$
( C ) $\frac{1}{\sqrt{2}}$
( D ) $\frac{3}{4}$