It is given that the events A and B are such that $P(A)=\frac{1}{4}P\bigg(\frac{A}{B}\bigg)=\frac{1}{2}$$P\bigg(\frac{B}{A}\bigg)=\frac{2}{3}$.Then P(B) is

Question

( A ) $\frac{2}{3}$
( B ) $\frac{1}{3}$
( C ) $\frac{1}{2}$
( D ) $\frac{1}{6}$