Given $E^o_{\frac{Cr^3+}{Cr}}=-0.72V$,$E^o_{\frac{Fe^2+}{Fe}}=-0.42V$.The potential for the cell $Cr|Cr^{3+}(0.1 M)| |Fe^{2+}(0.01 M)|Fe$ is

Question

( A ) 0.26 V
( B ) 0.399 V
( C ) -0.339 V
( D ) -0.26 V