Let $f(x) = (x+1)^2 - 1, x \geq -1$ <br> Statement -1 : The set $\{ x : f(x) = f^{-1} (x) \} = \{0, -1\}$ <br> Statement-2: f is a bijection.

Question

( A ) Statement-1 is false, Statement-2 is true
( B ) Statement-1 is true, Statement 2 is true; Statement-2 is a correct explanation for Statement-1
( C ) Statement-1 is true, Statement-2 is false
( D ) Statement-1 is true, Statement 2 is true; Statement-2 is not a correct explanation for Statement-1