Statement -1: The variance of first n even natural numbers is $\frac{n^2-1}{4}$ <br> Statement -2 :The sum of first $n$ natural numbers is $\frac{n(n+1)}{2}$ and the sum of squares of first $n$ natural numbers is $\frac{n(n+1)(2n+1)}{6}$

Question

( A ) Statement-1 is true, Statement-2 is false
( B ) Statement-1 is true, Statement 2 is true; Statement-2 is not a correct explanation for Statement-1
( C ) Statement-1 is true, Statement 2 is true; Statement-2 is a correct explanation for Statement-1
( D ) Statement-1 is false, Statement-2 is true