# A uniform rod of length $'l'$ whose mass per unit length is $\lambda$. The gravitational force on a particle of mass m located at a distance d from one end of the rod as shown is
$(a)\;\frac{Gm\lambda l}{d(d+l)} \quad (b)\;\frac{Gm\lambda }{l(d+l)} \quad (c)\;\frac{Gml}{\lambda(d+l)} \quad (d)\;\frac{2Gm\lambda l}{d(d+l)}$