A square has an area of $49 \;in^2$. If the side of the square is the same as the diameter of the circle, what is the area of the circle ?

Question

$\begin{array}{1 1} (a)\; 49 \pi \;in^2 \\ (b)\; \frac{49}{2} \pi \;in^2 \\ (c)\; \frac{49 \pi}{4} \;in^2 \\ (d)\; \text{none of the above} \end{array}$