The standard enthalpy of formation of $NH_3$ is $–46.0\; kJ mol^{–1}.$ If the enthalpy of formation of $H_2$ from its atoms is $–436\; kJ mol^{–1}$ and that of $N_2$ is $–712\; kJ mol^{–1},$ the average bond enthalpy of $N–H$ bond in $NH_3$ is

Question

( A ) $–964 kJ mol^{–1}$
( B ) $+1056 kJ mol^{–1}$
( C ) $–1102 kJ mol^{–1}$
( D ) $+352 kJ mol^{–1}$