At $25^{\circ}C$, the solubility product of $Mg(OH)_2$ is $1.0 \times 10^{–11}$. At which $pH$, will $Mg^{2+}$ ions start precipitating in the form of $Mg(OH)_2$ from a solution of $0.001\; M \;Mg^{2+}$ ions ?

Question

( A ) 9
( B ) 11
( C ) 8
( D ) 10