A rectangular loop has a sliding connector PQ of length A and resistance $R \Omega$ and it is moving with a speed v as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents $I_1, I_2$ and I are

Question

( A ) $I_1=I_1 - \frac{BAv}{6R}I- \frac{2BAv}{3R}$
( B ) $I_1=-I_2 - \frac{BAv}{R}I- \frac{2BAv}{R}$
( C ) $I_1=I_2 - \frac{BAv}{3R}I$
( D ) $I_1=-I_2 - \frac{BAv}{3R}I- \frac{2BAv}{3R}$