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JEEMAIN PAST PAPERS
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2010
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Q)
The equation of a wave on a string of linear mass density $0.04\; kg\;m^{-1}$ is given by$ y = 0.02 (m) \sin [ 2 \pi (\frac{t}{0.04 (s)} - \frac{x}{0.50(m)} ) ]$. The tension in the string is
( A ) 6.25 N
( B ) 12.5 N
( C ) 0.5 N
( D ) 4.0 N
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