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If the lines $\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{4}$ and $ \frac{x-3}{1} = \frac{y-k}{2} = \frac{z}{1}$ intersect, then $k$ is equal to


( A ) $0$
( B ) $-1$
( C ) $\frac{2}{9}$
( D ) $\frac{9}{2}$

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