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JEEMAIN and NEET
>>
JEEMAIN PAST PAPERS
>>
2013
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Q)
Given <br>
E
0
C
r
3
+
/
C
r
=
−
0.74
V
;
E
0
M
n
O
−
4
/
M
n
2
+
=
1.51
V
<br>
E
0
C
r
2
O
2
−
7
/
C
r
3
+
=
1.33
V
;
E
0
C
l
/
C
l
−
=
1.36
V
<br> Based on the data given abov, strongest oxidising agent will be :
( A )
M
n
2
+
( B )
M
n
O
−
4
( C )
C
r
3
+
( D )
C
l
−
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