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Q)

If f(x)dx=Ψ(x), then x5f(x3)dx is equal to


( A ) 13[x3Ψ(x3)x2Ψ(x3)dx]+C
( B ) 13x3Ψ(x3)x3Ψ(x3)dx+C
( C ) 13[x3Ψ(x3)x3Ψ(x3)dx]+C
( D ) 13x3Ψ(x3)x2Ψ(x3)dx+C
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