The image of the line $\frac{x-1}{3} = \frac{y-3}{1} = \frac{z-4}{-5}$ in the plane $2x-y+z+3 = 0$ is the line

Question

( A ) $\frac{x-3}{-3} = \frac{y+5}{-1} = \frac{z-2}{5}$
( B ) $\frac{x+3}{3} = \frac{y-5}{1} = \frac{z-2}{-5}$
( C ) $\frac{x+3}{-3} = \frac{y-5}{-1} = \frac{z+2}{5}$
( D ) $\frac{x-3}{3} = \frac{y+5}{1} = \frac{z-2}{-5}$