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Q)

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance $\frac{2A}{3} $ from equilibrium position. The new amplitude of the motion is :


( A ) $\frac{7A}{3}$
( B ) $A\sqrt{3}$
( C ) $\frac{A}{3} \sqrt{41}$
( D ) $3A$

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