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JEEMAIN PAST PAPERS
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2016
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Q)
Let P be the point on the parabola, $y^2=8x$ which is at a minimum distance from the centre C of the circle, $x^2+(y+6)^2=1$. Then the equation of the circle, passing through C and having its centre at P is :
( A ) $x^2+y^2−4x+9y+18=0$
( B ) $x^2+y^2−x+4y−12=0$
( C ) $x^2+y^2− \frac{ x}{4} +2y−24=0$
( D ) $x^2+y^2−4x+8y+12=0$
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