Let $a_1, a_2, a_3,.....,a_{49}$ be in A.P. such that $\displaystyle\sum_{k=0}^{12} a_{4k+1}=416$ and $a_9 + a_{43} =66$. <br> If $a_1^2 + a_2^2....a_{17}^2=140\;m$ then $m$ is equal to :

Question

( A ) 68
( B ) 33
( C ) 34
( D ) 66