The ratio of mass percent of $C$ and $H$ of an organic compound $(C_XH_YO_Z)$ is $6:1$. If one molecule of the above compound $(C_XH_YO_Z)$ contains half as much oxygen as required to burn one molecule of compound $C_XH_Y$ completely to $CO_2$ and $H_2O$. The empirical formula of compound $C_XH_YO_Z$ is :

Question

( A ) $C_2H_4O_3$
( B ) $C_3H_6O_3$
( C ) $C_2H_4O$
( D ) $C_3H_4O_2$