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The solubility in water of a sparingly soluble salt $AB_2$ is $1.0 \times 10^{-5} mol\;L^{-1}$. Its solubility product number will be :


( A ) $4 \times 10^{-10}$
( B ) $1 \times 10^{-15}$
( C ) $1 \times 10^{-10}$
( D ) $4 \times 10^{-15}$

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