For the redox reaction <br> $Zn(s) + Cu^{2+} (0.1 M) \to Zn^{2+} (1M) + Cu(s)$ <br> taking place in a cell, $E^{\circ}_{cell}$ is $1.10\; volt$. $E_{cell}$ for the cell will be : $(2.303 \frac{RT}{F}= 0.0591 )$

Question

( A ) 0.82 V
( B ) 1.80 V
( C ) 2.14 V
( D ) 1.07 V