$\displaystyle\lim_{n \to \infty} \frac{1 + 2^4 + 3^4 + ...+ n^4}{n^5} - \displaystyle\lim_{n \to \infty} \frac{1+2^3 + 3^3 + ....+ n^3}{n^5}$ is :

Question

( A ) $1/5$
( B ) $0$
( C ) $1/4$
( D ) $1/30$