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JEEMAIN and NEET
>>
JEEMAIN PAST PAPERS
>>
2003
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Q)
If the equation of the locus of a point equidistant from the points
(
a
1
,
b
1
)
and
(
a
2
,
b
2
)
is
(
a
1
−
a
2
)
x
+
(
b
1
−
b
2
)
y
+
c
=
0
, then the value of
′
C
′
is :
( A )
1
2
(
a
2
2
+
b
2
2
−
a
2
1
−
b
2
1
)
( B )
a
2
1
−
a
2
2
+
b
2
1
−
b
2
2
( C )
√
a
2
1
+
b
2
1
−
a
2
2
−
b
2
2
( D )
1
2
(
a
2
1
+
a
2
2
+
b
2
1
+
b
2
2
)
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