Two systems of rectangular axes have the same origin. If a plane cuts them at distances $a, \; b,\; c$ and $a',\;b',\;c'$ from the origin, then :

Question

( A ) $\begin{align*}\frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2} + \frac{1}{a'^2} + \frac{1}{b'^2} + \frac{1}{c'^2} = 0 \end{align*}$
( B ) $\begin{align*}\frac{1}{a^2} - \frac{1}{b^2} - \frac{1}{c^2} + \frac{1}{a'^2} - \frac{1}{b'^2} - \frac{1}{c'^2} = 0 \end{align*}$
( C ) $\begin{align*}\frac{1}{a^2} + \frac{1}{b^2} - \frac{1}{c^2} + \frac{1}{a'^2} + \frac{1}{b'^2} - \frac{1}{c'^2} = 0 \end{align*}$
( D ) $\begin{align*}\frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2} - \frac{1}{a'^2} - \frac{1}{b'^2} - \frac{1}{c'^2} = 0 \end{align*}$