The solution of the equation $\frac{d^2y}{dx^2} = e^{-2x}$ is

Question

( A ) $\frac{1}{4} e^{-2x} + c + d$
( B ) $\frac{e^{-2x}}{4}$
( C ) $\frac{e^{-2x}}{4} + cx + d$
( D ) $\frac{1}{4} e^{-2x} + cx^2 + d$