Let $f(2) = 4$ and $f'(2) = 4$. Then $\begin{align*} \displaystyle\lim_{x \to 2} \frac{xf(2) - 2 f(x)}{x-2} \end{align*}$ is given by :

Question

( A ) $3$
( B ) $-4$
( C ) $-2$
( D ) $2$