If $\tan \theta = -\frac{4}{3}$, then $\sin \theta$ is :

Question

( A ) $\frac{4}{5}$ but not $-\frac{4}{5}$
( B ) $-\frac{4}{5}$ or $\frac{4}{5}$
( C ) none of these
( D ) $-\frac{4}{5}$ but not $\frac{4}{5}$