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The de-Broglie wavelength of an electron having $80\;eV$ energy is nearly : <br> ($1\;eV = 1.6 \times 10^{-19} J $) <br> Mass of electron = $9 \times 10^{-31} kg $ <br> Planck's constant = $6.6 \times 10^{-34} Js $)


( A ) $140 \mathring{A}$
( B ) $14 \mathring{A}$
( C ) $0.14 \mathring{A}$
( D ) $1.4 \mathring{A}$

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