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Consider the following reactions <br> $C_2H_2 \xrightarrow[\text{500$^{\circ}$C}]{\text{red hot iron tube}} A$ <br><br> $A \xrightarrow[\text{70$^{\circ}$C}]{\text{conc. $HNO_3$, conc. $H_2SO_4$}} B$ <br><br> $B \xrightarrow{LiAlH_4} C_6H_5 - N = N - C_6H_5$ <br>A and B are :


( A ) $A = C_2H_4, \; B = C_6H_5NH_2$
( B ) $A = C_6H_6, \; B = C_6H_5NO_2$
( C ) $A = C_2H_4, \; B= C_6H_6$
( D ) $A = C_2H_6, \; B = C_6H_5NH_2$

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