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The lines $2x + 3y = 6, \; 2x + 3y = 8$ cut the $x$-axis at $A$ and $B$ respectively. A line L drawn through the point $(2,2)$ meets the $x$-axis as $C$ in such a way that abscissae of A, B and C are in arithmetic progression. Then the equation of the line L is :


( A ) $2x + 3y =10$
( B ) $8x - 2y = 10$
( C ) $8x+ 2y = 10$
( D ) $2x - 3y = 10$

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