If $h(x) = x^{x^2}$, then at $x=1$ $\frac{h'(x)}{h(x)}$ is equal to :

Question

( A ) $-\log h(x)$
( B ) $\frac{1}{h(x)}$
( C ) $1 + \log h(x)$
( D ) $h(x)$